Direction Cosines And Direction Ratios
A line makes equal acute angles with the three coordinate axes, so what is the value of each of its direction cosines?
Select the correct option:
Solution
1/3
The governing identity here is the fundamental relation for direction cosines: if l, m, n are the cosines of the angles a line makes with the x, y and z axes, then l^2 + m^2 + n^2 = 1. This constraint always holds for any line in space, which is the core JEE Advanced fact being probed. Since the line makes equal acute angles with all three axes, l = m = n. Substituting into the identity gives 3l^2 = 1, so l^2 = 1/3 and l = \pm 1/\sqrt{3}. Because the angles are acute, the cosines are positive, hence each direction cosine equals 1/\sqrt{3}. Option 1/3 is wrong because that is the value of l^2, not l. Option \sqrt{3} is impossible since a cosine cannot exceed 1. Option 1/\sqrt{2} would force l^2 + m^2 + n^2 = 3/2 \neq 1, violating the identity. This uses the standard direction-cosine normalization theorem. Plausibility check: 1/\sqrt{3} \approx 0.577 corresponds to an angle of about 54.7 degrees, which is acute and consistent with three equal positive cosines summing in square to one.
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About This Question
- Subject
- mathematics
- Chapter
- three dimensional geometry
- Topic
- direction cosines and direction ratios
- Difficulty
- Easy
- Year
- 2025
Solution
Correct Answer:
1/3
The governing identity here is the fundamental relation for direction cosines: if l, m, n are the cosines of the angles a line makes with the x, y and z axes, then l^2 + m^2 + n^2 = 1. This constraint always holds for any line in space, which is the core JEE Advanced fact being probed. Since the line makes equal acute angles with all three axes, l = m = n. Substituting into the identity gives 3l^2 = 1, so l^2 = 1/3 and l = \pm 1/\sqrt{3}. Because the angles are acute, the cosines are positive, hence each direction cosine equals 1/\sqrt{3}. Option 1/3 is wrong because that is the value of l^2, not l. Option \sqrt{3} is impossible since a cosine cannot exceed 1. Option 1/\sqrt{2} would force l^2 + m^2 + n^2 = 3/2 \neq 1, violating the identity. This uses the standard direction-cosine normalization theorem. Plausibility check: 1/\sqrt{3} \approx 0.577 corresponds to an angle of about 54.7 degrees, which is acute and consistent with three equal positive cosines summing in square to one.
This easy difficulty mathematics question is from the chapter three dimensional geometry, covering the topic of direction cosines and direction ratios. It appeared in the 2025 exam.
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