Dimensional Analysis (planck Constant)
Dimensions of Planck's constant h are?
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About This Question
- Subject
- physics
- Chapter
- physics and measurement
- Topic
- dimensional analysis (planck constant)
- Difficulty
- Medium
- Year
- 2025
Solution
- Base Equation: Start from E=hν (Photon energy), where E is energy and ν is frequency.
- Isolate h: h=E/ν.
- Dimensional Analysis:
- [E]=[ML2T−2]
- [ν]=[T−1] (reciprocal of time period)
- Calculation:
- [h]=[T−1][ML2T−2]
- [h]=[ML2T−2+1]=[ML2T−1].
- Note: These are the same dimensions as Angular Momentum (L=rmv or [L][M][LT−1]=[ML2T−1]).
This medium difficulty physics question is from the chapter physics and measurement, covering the topic of dimensional analysis (planck constant). It appeared in the 2025 exam.
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