Differentiability
Using chain rule, d/dx[sin(x²)] equals
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Solution
2x cos(x²)
- Chain Rule Statement: dxdf(g(x))=f′(g(x))⋅g′(x).
- Identify Functions:
- Outer function f(u)=sinu⟹f′(u)=cosu.
- Inner function u=g(x)=x2⟹g′(x)=2x.
- Application:
- dxd[sin(x2)]=cos(x2)⋅dxd(x2)
- =cos(x2)⋅(2x)
- Result: 2xcos(x2).
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About This Question
- Subject
- mathematics
- Chapter
- limit, continuity and differentiability
- Topic
- differentiability
- Difficulty
- Medium
- Year
- 2025
Solution
Correct Answer:
2x cos(x²)
- Chain Rule Statement: dxdf(g(x))=f′(g(x))⋅g′(x).
- Identify Functions:
- Outer function f(u)=sinu⟹f′(u)=cosu.
- Inner function u=g(x)=x2⟹g′(x)=2x.
- Application:
- dxd[sin(x2)]=cos(x2)⋅dxd(x2)
- =cos(x2)⋅(2x)
- Result: 2xcos(x2).
This medium difficulty mathematics question is from the chapter limit, continuity and differentiability, covering the topic of differentiability. It appeared in the 2025 exam.
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