dielectric effect hard

Question

Inserting dielectric (K>1) fully into isolated charged capacitor (battery disconnected) causes potential difference to:

RankGuru · Accepted Answer

1. Since the battery is disconnected, the **Charge $Q$ remains constant**.
2. Inserting a dielectric increases the capacitance: $C' = KC$ ($K>1$).
3. From $V = Q/C$:
Since $Q$ is constant and $C$ increases, the potential difference $V$ must **Decrease** by a factor of $K$ ($V' = V/K$).

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dielectric effect hard

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