Dielectric
A dielectric of dielectric constant K = 5 is inserted between the plates of a parallel plate capacitor. How does the capacitance change?
Select the correct option:
Solution
Becomes 5 times
- Capacitance without Dielectric: C0=dϵ0A.
- Capacitance with Dielectric: C=dϵA=dKϵ0A.
- Effect: The insertion of a dielectric material replaces vacuum/air with a substance that polarizes, reducing the internal field and allowing the capacitor to store more charge for the same voltage.
- Result: The new capacitance C=K×C0=5×C0.
- Conclusion: It becomes 5 times the original value.
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About This Question
- Subject
- physics
- Chapter
- electrostatics
- Topic
- dielectric
- Difficulty
- Easy
- Year
- 2025
Solution
Correct Answer:
Becomes 5 times
- Capacitance without Dielectric: C0=dϵ0A.
- Capacitance with Dielectric: C=dϵA=dKϵ0A.
- Effect: The insertion of a dielectric material replaces vacuum/air with a substance that polarizes, reducing the internal field and allowing the capacitor to store more charge for the same voltage.
- Result: The new capacitance C=K×C0=5×C0.
- Conclusion: It becomes 5 times the original value.
This easy difficulty physics question is from the chapter electrostatics, covering the topic of dielectric. It appeared in the 2025 exam.
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