Dielectric

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A dielectric of dielectric constant K = 5 is inserted between the plates of a parallel plate capacitor. How does the capacitance change?

RankGuru · Accepted Answer

1. **Capacitance without Dielectric**: $C_0 = \frac{\epsilon_0 A}{d}$.
2. **Capacitance with Dielectric**: $C = \frac{\epsilon A}{d} = \frac{K \epsilon_0 A}{d}$.
3. **Effect**: The insertion of a dielectric material replaces vacuum/air with a substance that polarizes, reducing the internal field and allowing the capacitor to store more charge for the same voltage.
4. **Result**: The new capacitance $C = K 	imes C_0 = 5 	imes C_0$.
5. **Conclusion**: It becomes **5 times** the original value.

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