Degree Of Dissociation
At 500 K, for the reaction PCl₅(g) ⇌ PCl₃(g) + Cl₂(g), if the degree of dissociation is 0.4 and initial concentration of PCl₅ is 1 M, the value of Kc is:
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About This Question
- Subject
- chemistry
- Chapter
- equilibrium
- Topic
- degree of dissociation
- Difficulty
- Medium
- Year
- 2025
Solution
Correct Answer:
0.267
Reaction: PCl5(g)⇌PCl3(g)+Cl2(g)
- Initial concentrations: [PCl5]0=1.0 M,[PCl3]=0,[Cl2]=0
- Degree of dissociation (α)=0.4 At equilibrium:
- [PCl5]=C(1−α)=1.0(1−0.4)=0.6 M
- [PCl3]=Cα=1.0×0.4=0.4 M
- [Cl2]=Cα=1.0×0.4=0.4 M Calculation of Kc: Kc=[PCl5][PCl3][Cl2]=0.60.4×0.4=0.60.16=0.2667≈0.267
This medium difficulty chemistry question is from the chapter equilibrium, covering the topic of degree of dissociation. It appeared in the 2025 exam.
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