Decarboxylation
Easychemistry
Decarboxylation of sodium acetate with soda lime gives:
Select the correct option:
Solution
Incorrect! Answer:
Methane
Decarboxylation involves the removal of the carboxyl group as CO2.
- Reagent: Soda Lime (a mixture of NaOH and CaO in a 3:1 ratio).
- Reaction: CH3COONa+NaOH(CaO)ΔCH4+Na2CO3
- The reaction yields an alkane with one less carbon atom than the parent carboxylate salt.
- From Sodium acetate (2 carbons), we obtain Methane (1 carbon).
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About This Question
- Subject
- chemistry
- Chapter
- organic compounds containing oxygen
- Topic
- decarboxylation
- Difficulty
- Easy
- Year
- 2025
Solution
Correct Answer:
Methane
Decarboxylation involves the removal of the carboxyl group as CO2.
- Reagent: Soda Lime (a mixture of NaOH and CaO in a 3:1 ratio).
- Reaction: CH3COONa+NaOH(CaO)ΔCH4+Na2CO3
- The reaction yields an alkane with one less carbon atom than the parent carboxylate salt.
- From Sodium acetate (2 carbons), we obtain Methane (1 carbon).
This easy difficulty chemistry question is from the chapter organic compounds containing oxygen, covering the topic of decarboxylation. It appeared in the 2025 exam.
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