De Broglie Wavelength Of A Macroscopic Object
A cricket-style practice ball of mass 50 g is thrown so that it moves with a speed of 20 m s−1 across a field. What is the de Broglie wavelength associated with this moving ball?
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Solution
6.6×10−34 m
The de Broglie relation λ=mvh applies to every moving object, not just electrons, but the wavelength becomes utterly negligible for macroscopic masses. Here the momentum is mv=0.050×20=1.0 kg m s−1, so λ=1.06.6×10−34=6.6×10−34 m. The value 6.6×10−31 m misplaces three powers of ten by treating the mass as grams. The value 3.3×10−34 m doubles the momentum. The value 1.3×10−33 m halves the momentum. This wavelength is some twenty orders of magnitude smaller than an atomic nucleus, far too tiny to produce any observable diffraction or interference, which is exactly why the wave nature of everyday objects is completely undetectable. The matter-wave concept only reveals itself for very light particles such as electrons, as the NCERT chapter emphasises. A sanity check on magnitude confirms the result: because the mass is enormous on an atomic scale, the wavelength is vanishingly small, so the ball behaves as a purely classical particle. The deeper lesson is that wave-particle duality is universal in principle but observable only when the de Broglie wavelength is comparable to the size of the apertures or obstacles a particle encounters. For everyday objects no slit or grating is remotely fine enough, so their wave nature, though real in the formalism, can never manifest, leaving classical mechanics a complete and accurate description.
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About This Question
- Subject
- physics
- Chapter
- dual nature of radiation and matter
- Topic
- de broglie wavelength of a macroscopic object
- Difficulty
- Medium
- Year
- 2025
Solution
Correct Answer:
6.6×10−34 m
The de Broglie relation λ=mvh applies to every moving object, not just electrons, but the wavelength becomes utterly negligible for macroscopic masses. Here the momentum is mv=0.050×20=1.0 kg m s−1, so λ=1.06.6×10−34=6.6×10−34 m. The value 6.6×10−31 m misplaces three powers of ten by treating the mass as grams. The value 3.3×10−34 m doubles the momentum. The value 1.3×10−33 m halves the momentum. This wavelength is some twenty orders of magnitude smaller than an atomic nucleus, far too tiny to produce any observable diffraction or interference, which is exactly why the wave nature of everyday objects is completely undetectable. The matter-wave concept only reveals itself for very light particles such as electrons, as the NCERT chapter emphasises. A sanity check on magnitude confirms the result: because the mass is enormous on an atomic scale, the wavelength is vanishingly small, so the ball behaves as a purely classical particle. The deeper lesson is that wave-particle duality is universal in principle but observable only when the de Broglie wavelength is comparable to the size of the apertures or obstacles a particle encounters. For everyday objects no slit or grating is remotely fine enough, so their wave nature, though real in the formalism, can never manifest, leaving classical mechanics a complete and accurate description.
This medium difficulty physics question is from the chapter dual nature of radiation and matter, covering the topic of de broglie wavelength of a macroscopic object. It appeared in the 2025 exam.
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