De Broglie Wavelength
An electron is accelerated through a potential difference of 100 V. Its de Broglie wavelength is approximately:
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About This Question
- Subject
- chemistry
- Chapter
- atomic structure
- Topic
- de broglie wavelength
- Difficulty
- Hard
- Year
- 2025
Solution
Correct Answer:
0.123 nm
The de Broglie Wavelength (λ) of an accelerated electron is given by: λ=ph=2meVh Using standard values for h,m,e, the approximate formula is: λ≈V150 A˚≈V12.27 A˚ Given V=100 V: λ=10012.27=1012.27=1.227 A˚ Since 1 nm=10 A˚: λ≈0.1227 nm≈0.123 nm
This hard difficulty chemistry question is from the chapter atomic structure, covering the topic of de broglie wavelength. It appeared in the 2025 exam.
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