Covalent Bond

Question

The bond order of N₂ molecule is:

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According to **Molecular Orbital Theory (MOT)**, the electronic configuration of $N_2$ (14 electrons) is:
$\sigma 1s^2 \sigma^* 1s^2 \sigma 2s^2 \sigma^* 2s^2 (\pi 2p_x^2 = \pi 2p_y^2) \sigma 2p_z^2$
- Number of bonding electrons ($N_b$) = 10
- Number of anti-bonding electrons ($N_a$) = 4
$Bond \, Order = \frac{N_b - N_a}{2} = \frac{10 - 4}{2} = \frac{6}{2} = 3$
- A bond order of 3 indicates a very strong **triple bond** ($N \equiv N$), which explains its high dissociation energy.

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Covalent Bond

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