Coulomb's Law (numerical)
Mediumphysics
Two charges 2×10⁻⁶ C and 3×10⁻⁶ C are 0.20 m apart. Force magnitude? (k = 9×10⁺⁹ N·m²/C²)
Select the correct option:
Solution
Incorrect! Answer:
1.35 N
- Identify Given Data:
- q1=2×10−6 C
- q2=3×10−6 C
- r=0.20 m
- k=9×109 N m2/C2
- Substitute in Coulomb's Law Formula:
- F=kr2q1q2
- F=9×109×(0.2)2(2×10−6)×(3×10−6)
- Calculation:
- F=9×109×0.046×10−12
- F=0.0454×10−3=0.040.054
- F=1.35 N.
- Result: The magnitude of the force is 1.35 N.
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About This Question
- Subject
- physics
- Chapter
- electrostatics
- Topic
- coulomb's law (numerical)
- Difficulty
- Medium
- Year
- 2025
Solution
Correct Answer:
1.35 N
- Identify Given Data:
- q1=2×10−6 C
- q2=3×10−6 C
- r=0.20 m
- k=9×109 N m2/C2
- Substitute in Coulomb's Law Formula:
- F=kr2q1q2
- F=9×109×(0.2)2(2×10−6)×(3×10−6)
- Calculation:
- F=9×109×0.046×10−12
- F=0.0454×10−3=0.040.054
- F=1.35 N.
- Result: The magnitude of the force is 1.35 N.
This medium difficulty physics question is from the chapter electrostatics, covering the topic of coulomb's law (numerical). It appeared in the 2025 exam.
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