Conductors And Ohmic Behaviour
When the temperature of a pure metallic conductor is raised, which statement correctly describes the resulting change in its electrical conductivity?
Select the correct option:
Solution
Conductivity decreases because increased lattice vibrations scatter electrons more
Electrical conductivity in a metal is governed by how freely its abundant conduction electrons move between collisions, expressed through (\sigma = \frac{ne^2\tau}{m}), where (\tau) is the mean time between collisions. In a pure metal the free-electron density (n) is essentially fixed, so the temperature behaviour is controlled by (\tau). Raising the temperature makes the lattice ions vibrate more vigorously, so electrons collide more often and (\tau) decreases, lowering the conductivity and equivalently raising resistivity. Hence the first statement is correct. The second is wrong because, unlike semiconductors, metals do not gain appreciable extra carriers on heating. The third is wrong because charge conservation says nothing about how easily charge moves. The fourth confuses cause and effect, since increased scattering actually reduces the average drift, not increases it. This reflects the NCERT free-electron treatment of metallic conduction. A plausibility check confirms it: experimentally, metals are known to grow more resistive when heated, which is exactly a fall in conductivity, consistent with the chosen statement.
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About This Question
- Subject
- physics
- Chapter
- current electricity
- Topic
- conductors and ohmic behaviour
- Difficulty
- Easy
- Year
- 2025
Solution
Correct Answer:
Conductivity decreases because increased lattice vibrations scatter electrons more
Electrical conductivity in a metal is governed by how freely its abundant conduction electrons move between collisions, expressed through (\sigma = \frac{ne^2\tau}{m}), where (\tau) is the mean time between collisions. In a pure metal the free-electron density (n) is essentially fixed, so the temperature behaviour is controlled by (\tau). Raising the temperature makes the lattice ions vibrate more vigorously, so electrons collide more often and (\tau) decreases, lowering the conductivity and equivalently raising resistivity. Hence the first statement is correct. The second is wrong because, unlike semiconductors, metals do not gain appreciable extra carriers on heating. The third is wrong because charge conservation says nothing about how easily charge moves. The fourth confuses cause and effect, since increased scattering actually reduces the average drift, not increases it. This reflects the NCERT free-electron treatment of metallic conduction. A plausibility check confirms it: experimentally, metals are known to grow more resistive when heated, which is exactly a fall in conductivity, consistent with the chosen statement.
This easy difficulty physics question is from the chapter current electricity, covering the topic of conductors and ohmic behaviour. It appeared in the 2025 exam.
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