Skip to content

Common Roots

Mediummathematics

If the two quadratic equations x^2 + bx + c = 0 and x^2 + cx + b = 0, with b not equal to c, share exactly one common root, then the value of b + c equals which expression?

Select the correct option:

🔒 Solution Hidden from View

Submit your answer to unlock the detailed step-by-step solution.

More complex numbers and quadratic equations Practice Questions

HardJEE_ADVANCED

The set of all complex numbers z satisfying the equation given by the ratio condition arg of the qua...

View Solution→
HardJEE_ADVANCED

If the equation x^2 - (k - 3)x + k = 0 has both roots real, then the set of all real values of the p...

View Solution→
HardJEE_ADVANCED

Among all complex numbers z lying on the circle defined by |z| = 1, the maximum value attained by th...

View Solution→
MediumJEE_ADVANCED

If alpha and beta are roots of x^2 - 2x + 4 = 0, then the value of the symmetric expression alpha cu...

View Solution→
MediumJEE_ADVANCED

The values of the real parameter m for which the quadratic equation (m + 1)x^2 + 2(m + 3)x + (m + 8)...

View Solution→
EasyJEE_ADVANCED

For any complex number z, the expression z multiplied by its conjugate z-bar is always equal to whic...

View Solution→
EasyJEE_ADVANCED

If two complex numbers have moduli 2 and 5 and arguments 40 degrees and 80 degrees respectively, the...

View Solution→
EasyJEE_ADVANCED

For all real x, the quadratic expression f(x) = x^2 - 6x + 11 attains a minimum value, and that mini...

View Solution→
MediumJEE_ADVANCED

If alpha and beta are the roots of x^2 - 4x + 1 = 0, then the quadratic equation whose roots are the...

View Solution→
MediumJEE_ADVANCED

If one root of the real-coefficient quadratic x^2 + px + q = 0 is the complex number 2 + 3i, then th...

View Solution→
EasyJEE_ADVANCED

For a complex number z satisfying the constraint |z - 4| ≤ 3, the maximum possible value of the modu...

View Solution→
EasyJEE_ADVANCED

The sum of all the distinct fifth roots of unity in the complex plane, taken together as complex num...

View Solution→

Browse all complex numbers and quadratic equations questions →

About This Question

Subject
mathematics
Chapter
complex numbers and quadratic equations
Topic
common roots
Difficulty
Medium
Year
2025
Tags
advanced-calculus-drillcommon-rooteliminationquadratic-systemtheory-of-equations

Solution

Correct Answer:

When two quadratics share a common root, subtracting them eliminates the squared term and isolates that root, the canonical JEE Advanced common-root method. Subtracting the second equation from the first gives (b - c)x + (c - b) = 0, that is (b - c)x - (b - c) = 0. Since b ≠ c we may divide by (b - c) to get x - 1 = 0, so the common root is x = 1. Substituting x = 1 into the first equation gives 1 + b + c = 0, hence b + c = -1. The elimination step turning two quadratics into a linear relation is the key archetype. Option 0 ignores the constant from substitution. Option 1 has the wrong sign. Option cannot be determined overlooks that the common root is forced to be 1. Hence b + c = -1. Plausibility check: with b + c = -1 the common root 1 satisfies both equations identically, and the condition b ≠ c keeps the two quadratics genuinely different, confirming consistency. Eliminating the squared term by subtracting two quadratics is the universal opening move for common-root problems, reducing the system to a single linear equation that pins down the shared root. Substituting that root back into either original equation then recovers the relation among the coefficients, and the condition that the two quadratics remain distinct is what keeps the division step legitimate.

This medium difficulty mathematics question is from the chapter complex numbers and quadratic equations, covering the topic of common roots. It appeared in the 2025 exam.

Looking for more practice? Explore all mathematics questions or browse complex numbers and quadratic equations questions on RankGuru.