Circular Motion (f=ma)
A 0.5 kg stone tied to a string moves in a horizontal circle of radius 1.2 m at constant speed 6 m/s. Find tension in the string.
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About This Question
- Subject
- physics
- Chapter
- laws of motion
- Topic
- circular motion (f=ma)
- Difficulty
- Medium
- Year
- 2025
Solution
Correct Answer:
15 N
- Centripetal Requirement: For horizontal circular motion, the tension (T) in the string provides the necessary centripetal force (Fc).
- Formula: Fc=rmv2.
- Identify Parameters:
- Mass (m) =0.5 kg
- Velocity (v) =6 m/s
- Radius (r) =1.2 m
- Calculation:
- T=1.20.5×62
- T=1.20.5×36=1.218
- T=15 N.
- Final Result: The tension in the string is 15 N.
This medium difficulty physics question is from the chapter laws of motion, covering the topic of circular motion (f=ma). It appeared in the 2025 exam.
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