Circular Loop Center Field
Field at center of circular loop radius R carrying current I?
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About This Question
- Subject
- physics
- Chapter
- magnetic effects and magnetism
- Topic
- circular loop center field
- Difficulty
- Medium
- Year
- 2025
Solution
Correct Answer:
μ0 I /(2R)
- Biot-Savart Law: dB=4πμ0r2Idlsinθ.
- Integration for Circle: At the center, every current element dl is at distance R and is perpendicular to the radius (θ=90∘).
- Step-by-Step:
- B=∫4πμ0R2Idl=4πR2μ0I∫dl
- Since ∫dl=2πR (circumference):
- B=4πR2μ0I×(2πR)=2Rμ0I.
- Conclusion: The magnetic field strength at the center of the loop is 2Rμ0I.
This medium difficulty physics question is from the chapter magnetic effects and magnetism, covering the topic of circular loop center field. It appeared in the 2025 exam.
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