Cell Conductance
A conductivity cell filled with 0.1 M KCl has resistance 100 ohm and cell constant 1.29 cm^-1; what is the conductivity of the solution?
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About This Question
- Subject
- chemistry
- Chapter
- redox reactions and electrochemistry
- Topic
- cell conductance
- Difficulty
- Medium
- Year
- 2025
Solution
Correct Answer:
0.0129Scm−1
Conductivity (specific conductance) is related to measured resistance and the geometric cell constant by the relation κ = (cell constant)/resistance, because conductivity equals conductance multiplied by the cell constant, and conductance is the reciprocal of resistance. Here the cell constant is 1.29 cm^-1 and the resistance is 100 ohm. Substituting, κ = 1.29/100 = 0.0129 S cm^-1. The cell constant accounts for the fixed distance between electrodes divided by their cross-sectional area, converting a raw conductance into an intrinsic property of the solution. Option 0.129 S cm^-1 results from dropping a factor of ten in the resistance. Option 0.00129 S cm^-1 divides by an extra factor of ten. Option 1.29 S cm^-1 ignores the resistance entirely. This is the standard NCERT conductometric calculation used to standardise cells with KCl. Working through the logic step by step, rather than memorising the result, makes it clear why resistance measurement governs the behaviour seen here. This concept also bridges to Solutions and Some Basic Concepts in Chemistry, so mastering it strengthens performance on linked questions from those topics as well. Plausibility check: 0.1 M KCl has a known conductivity near 0.0129 S cm^-1, matching the computed result and confirming the calculation.
This medium difficulty chemistry question is from the chapter redox reactions and electrochemistry, covering the topic of cell conductance. It appeared in the 2025 exam.
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