carnot efficiency

Question

Carnot engine between 500 K and 300 K efficiency?

RankGuru · Accepted Answer

1. **Carnot Theorem**: No engine operating between two temperatures can be more efficient than a perfectly reversible Carnot engine.
2. **Efficiency Formula**: $\eta = 1 - \frac{T_{cold}}{T_{hot}}$, where temperatures must be in Kelvin.
3. **Given Data**:
   - $T_{hot} = 500$ K (Source)
   - $T_{cold} = 300$ K (Sink)
4. **Calculation**:
   - $\eta = 1 - \frac{300}{500} = 1 - 0.60$
   - $\eta = 0.40$.
5. **Unit Check**: Efficiency is a dimensionless ratio. In percentage terms, this is **$40\%$**.

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