Carius Method For Halogen Estimation
In Carius method, 0.245 g of an organic compound yields 0.287 g of AgCl. The percentage of chlorine in the compound is approximately:
Select the correct option:
Solution
29.0%
Moles of AgCl = 0.287/143.32 = 2.003 x 10^-3 mol. Each mole AgCl contains 1 mole Cl, so mass of Cl = 2.003 x 10^-3 x 35.45 = 0.0710 g. Percentage Cl = (0.0710/0.245) x 100 = 28.98%, approximately 29.0%. The value is consistent with expected stoichiometry and mass balance.
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About This Question
- Subject
- chemistry
- Chapter
- purification and characterisation of organic compounds
- Topic
- carius method for halogen estimation
- Difficulty
- Hard
- Year
- 2025
Solution
Correct Answer:
29.0%
Moles of AgCl = 0.287/143.32 = 2.003 x 10^-3 mol. Each mole AgCl contains 1 mole Cl, so mass of Cl = 2.003 x 10^-3 x 35.45 = 0.0710 g. Percentage Cl = (0.0710/0.245) x 100 = 28.98%, approximately 29.0%. The value is consistent with expected stoichiometry and mass balance.
This hard difficulty chemistry question is from the chapter purification and characterisation of organic compounds, covering the topic of carius method for halogen estimation. It appeared in the 2025 exam.
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