capacitors in series

Question

Two capacitors of 4 μF and 6 μF are connected in series. What is the equivalent capacitance?

RankGuru · Accepted Answer

1. **Series Rule for Capacitors**: The reciprocal of the equivalent capacitance is the sum of inverse capacitances.
   - Formula: $\frac{1}{C_{eq}} = \frac{1}{C_1} + \frac{1}{C_2}$.
2. **Short-cut for Two**: $C_{eq} = \frac{C_1 C_2}{C_1 + C_2}$.
3. **Calculation**:
   - $C_{eq} = \frac{4 	imes 6}{4 + 6} = \frac{24}{10}$.
4. **Result**: $C_{eq} = 2.4 	ext{ } \mu	ext{F}$.
5. **Note**: In series, the total charge $Q$ is identical on all capacitors, but voltage $V$ is divided.

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capacitors in series

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