Calorimetry Mixture
Mediumphysics
Final temperature when 0.2 kg water at 80°C mixed with 0.3 kg water at 20°C (no loss)?
Select the correct option:
Solution
Incorrect! Answer:
44°C
- Principle of Calorimetry: Heat lost by the hot body = Heat gained by the cold body.
- Equations: m1c(Thigh−Tf)=m2c(Tf−Tlow). Since both are water, specific heat c cancels out.
- Substitute:
- 0.2×(80−Tf)=0.3×(Tf−20)
- Solve:
- 16−0.2Tf=0.3Tf−6
- 16+6=0.3Tf+0.2Tf
- 22=0.5Tf⟹Tf=0.522=44∘C.
- Result: The equilibrium temperature is 44∘C.
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About This Question
- Subject
- physics
- Chapter
- thermodynamics
- Topic
- calorimetry mixture
- Difficulty
- Medium
- Year
- 2025
Solution
Correct Answer:
44°C
- Principle of Calorimetry: Heat lost by the hot body = Heat gained by the cold body.
- Equations: m1c(Thigh−Tf)=m2c(Tf−Tlow). Since both are water, specific heat c cancels out.
- Substitute:
- 0.2×(80−Tf)=0.3×(Tf−20)
- Solve:
- 16−0.2Tf=0.3Tf−6
- 16+6=0.3Tf+0.2Tf
- 22=0.5Tf⟹Tf=0.522=44∘C.
- Result: The equilibrium temperature is 44∘C.
This medium difficulty physics question is from the chapter thermodynamics, covering the topic of calorimetry mixture. It appeared in the 2025 exam.
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