Bond Enthalpy Approximation
Hardchemistry
Estimate ΔH (kJ mol⁻¹) for CH4(g) + 2O2(g) → CO2(g) + 2H2O(g) using average bond enthalpies. (Data approximate: C–H: 413, O=O: 498, C=O in CO2: 799, O–H: 463).
Select the correct option:
Solution
Incorrect! Answer:
-800 kJ mol⁻¹
- Formula: ΔH=∑BHbroken−∑BHformed.
- Bonds Broken (Reactants):
- 4×C−H = 4×413=1652 kJ.
- 2×O=O = 2×498=996 kJ.
- Total reactant energy = 2648 kJ.
- Bonds Formed (Products):
- 2×C=O (in CO2) = 2×799=1598 kJ.
- 2×2(O−H) (in 2H2O) = 4×463=1852 kJ.
- Total product energy = 3450 kJ.
- Calculation: ΔH=2648−3450=−802 kJ.
- Result: Roughly −800 kJ/mol.
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About This Question
- Subject
- chemistry
- Chapter
- chemical thermodynamics
- Topic
- bond enthalpy approximation
- Difficulty
- Hard
- Year
- 2025
This hard difficulty chemistry question is from the chapter chemical thermodynamics, covering the topic of bond enthalpy approximation. It appeared in the 2025 exam. Practice this and similar questions to strengthen your understanding of chemical thermodynamics concepts.
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