Bohr's Model

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In which orbit of hydrogen atom does the electron have an energy of -3.4 eV?

RankGuru · Accepted Answer

1. **Energy Formula for Hydrogen**: According to Bohr's model, the energy of an electron in the $n^{th}$ orbit is:
   - $E_n = -\frac{13.6}{n^2} 	ext{ eV}$.
2. **Given Data**: The energy is $E_n = -3.4 	ext{ eV}$.
3. **Set up Equation**:
   - $-3.4 = -\frac{13.6}{n^2}$
   - $n^2 = \frac{13.6}{3.4}$
4. **Calculation**:
   - $n^2 = 4 \implies n = \sqrt{4} = 2$.
5. **Conclusion**: The electron is in the **2nd orbit** (also known as the first excited state).

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Bohr's Model

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