Block On An Accelerating Surface
A block of mass 2 kg rests on the rough floor of a truck where the coefficient of static friction is 0.4. Taking g as 10 m/s^2, what is the maximum horizontal acceleration of the truck for which the block does not slide relative to it?
Select the correct option:
Solution
4m/s2
For the block to move with the truck, static friction between the block and floor must supply the force that accelerates the block at the same rate as the truck. The required force is ma, and friction can provide at most its limiting value μmg. The block stays put as long as ma≤μmg, so the maximum acceleration is when these are equal: amax=μg=0.4×10=4 m/s2. Notice the mass cancels, so the threshold is independent of how heavy the block is. The 2 m/s^2 value uses half the coefficient or omits a factor. The 6 m/s^2 and 8 m/s^2 values exceed the friction limit, meaning the block would actually slip backward relative to the truck at those accelerations. This is the NCERT and JEE friction-as-the-accelerating-agent scenario, and it overturns the common misconception that friction always opposes motion; here static friction actually points forward, in the direction of motion, because that is the only way to drag the block along with the truck. Were the truck to accelerate beyond μg, the block would lag and kinetic friction would take over at a fixed value, no longer able to keep pace. As a check, the answer μg has units of acceleration, and a rougher floor with larger μ would let the truck accelerate harder before sliding, which is physically reasonable.
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About This Question
- Subject
- physics
- Chapter
- laws of motion
- Topic
- block on an accelerating surface
- Difficulty
- Hard
- Year
- 2025
Solution
Correct Answer:
4m/s2
For the block to move with the truck, static friction between the block and floor must supply the force that accelerates the block at the same rate as the truck. The required force is ma, and friction can provide at most its limiting value μmg. The block stays put as long as ma≤μmg, so the maximum acceleration is when these are equal: amax=μg=0.4×10=4 m/s2. Notice the mass cancels, so the threshold is independent of how heavy the block is. The 2 m/s^2 value uses half the coefficient or omits a factor. The 6 m/s^2 and 8 m/s^2 values exceed the friction limit, meaning the block would actually slip backward relative to the truck at those accelerations. This is the NCERT and JEE friction-as-the-accelerating-agent scenario, and it overturns the common misconception that friction always opposes motion; here static friction actually points forward, in the direction of motion, because that is the only way to drag the block along with the truck. Were the truck to accelerate beyond μg, the block would lag and kinetic friction would take over at a fixed value, no longer able to keep pace. As a check, the answer μg has units of acceleration, and a rougher floor with larger μ would let the truck accelerate harder before sliding, which is physically reasonable.
This hard difficulty physics question is from the chapter laws of motion, covering the topic of block on an accelerating surface. It appeared in the 2025 exam.
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