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Beats

Easyphysics

A piano tuner sounds a reference fork of 256 Hz together with a slightly mistuned string, and hears the loudness rise and fall 4 times every second. What are the possible frequencies of the string?

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About This Question

Subject
physics
Chapter
oscillations and waves
Topic
beats
Difficulty
Easy
Year
2025
Tags
beatsbeat frequencysuperposition of soundfrequency differencetuning

Solution

Correct Answer:

or

When two sound waves of nearly equal frequency overlap, the resulting amplitude rises and falls periodically, producing beats whose frequency equals the absolute difference of the two source frequencies, . Here the tuner hears 4 beats per second against a 256 Hz fork, so the string differs from 256 Hz by exactly 4 Hz. Both possibilities satisfy this: or . The pair or is wrong because 256 Hz would give zero beats. The pair or corresponds to a beat frequency of 8 Hz, not 4 Hz. The pair or gives only 2 beats per second. This is the NCERT result that beat frequency equals the magnitude of the frequency difference. As a plausibility check, a single beat measurement cannot distinguish whether the string is sharp or flat, so two symmetric answers about the reference frequency are physically expected, which is exactly what and represent.

This easy difficulty physics question is from the chapter oscillations and waves, covering the topic of beats. It appeared in the 2025 exam.

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