Bandwidth Am

Mediumphysics

Bandwidth of AM signal equals:

Select the correct option:

Carrier frequency

Twice highest modulating frequency

Sum of all frequencies

Zero

🔒 Solution Hidden from View

Submit your answer to unlock the detailed step-by-step solution.

About This Question

Subject: physics
Chapter: communication systems
Topic: bandwidth am
Difficulty: Medium
Year: 2025

Solution

Correct Answer:

Twice highest modulating frequency

In a standard AM signal, the frequency spectrum consists of the carrier frequency $f_{c}$ and two sidebands:

Upper Sideband (USB): $f_{c} + f_{m}$
Lower Sideband (LSB): $f_{c} - f_{m}$ where $f_{m}$ is the frequency of the modulating signal. The bandwidth ( $B W$ ) is the difference between the highest and lowest frequencies: $B W = (f_{c} + f_{m}) - (f_{c} - f_{m}) = 2 f_{m}$ . Thus, the bandwidth of an AM signal is twice the highest frequency present in the modulating signal.

This medium difficulty physics question is from the chapter communication systems, covering the topic of bandwidth am. It appeared in the 2025 exam.

Looking for more practice? Explore all physics questions or browse communication systems questions on RankGuru.

Bandwidth Am

Select the correct option:

🔒 Solution Hidden from View

More communication systems Practice Questions

In FM, which parameter of carrier varies with modulating signal?

In AM, carrier amplitude varies proportional to:

Random undesirable variation in signal is termed:

Signal loss over distance in channel is termed:

Geostationary satellite orbits Earth with period equal to:

Sky wave propagation relies on reflection by:

Digital communication advantages include:

According to Shannon, channel capacity increases with bandwidth and:

Higher SNR implies received signal quality is:

Repeaters in long communication lines primarily:

In AM, modulation index m > 1 causes:

Error control coding introduces redundancy to:

About This Question

Solution