Balancing Redox Equations
In the reaction MnO₄⁻ + Fe²⁺ + H⁺ → Mn²⁺ + Fe³⁺ + H₂O (acidic medium), the ratio of MnO₄⁻ to Fe²⁺ is:
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About This Question
- Subject
- chemistry
- Chapter
- redox reactions and electrochemistry
- Topic
- balancing redox equations
- Difficulty
- Medium
- Year
- 2025
Solution
Correct Answer:
1:5
Using the Ion-Electron Method to balance the redox reaction:
- Reduction Half-reaction: MnO4−+8H++5e−→Mn2++4H2O
- (Oxidation state of Mn changes from +7 to +2, requiring 5e−).
- Oxidation Half-reaction: Fe2+→Fe3++e−
- (Oxidation state changes from +2 to +3, releasing 1e−).
- Electron Balance: To equalize electrons, multiply the oxidation half-reaction by 5.
- Result: 1MnO4− reacts with 5Fe2+.
- Therefore, the stoichiometric ratio is 1:5.
This medium difficulty chemistry question is from the chapter redox reactions and electrochemistry, covering the topic of balancing redox equations. It appeared in the 2025 exam.
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