average kinetic energy

Question

Average kinetic energy per molecule of ideal gas is:

RankGuru · Accepted Answer

The kinetic theory relates the macroscopic temperature ($T$) to the microscopic average translational kinetic energy ($\bar{K}$) of molecules:
$\bar{K} = \frac{1}{2} m \bar{v}^2 = \frac{3}{2} k_B T$
where:
- $k_B$ is the Boltzmann constant ($\approx 1.38 	imes 10^{-23} 	ext{ J/K}$).
- This result comes from the pressure equation $P = \frac{1}{3} \frac{N}{V} m \bar{v}^2$ and the ideal gas law $PV = N k_B T$.
- This energy depends **only on temperature**, not on the pressure, volume, or type of the ideal gas.

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average kinetic energy

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