Average Acceleration
Easyphysics
Velocity of a particle changes uniformly from 8 m/s east to 4 m/s west in 3 s. Magnitude of average acceleration?
Select the correct option:
Solution
Incorrect! Answer:
4 m/s²
- Sign Convention: Let East be the positive direction (+ velocity).
- Velocity Change:
- Initial velocity u=+8 m/s.
- Final velocity v=−4 m/s (West).
- Calculate Change ((\Delta v)): Δv=v−u=(−4)−(+8)=−12 m/s.
- Acceleration Formula: aavg=ΔtΔv=3 s−12 m/s=−4 m/s2.
- Magnitude: ∣aavg∣=4 m/s2.
- Result: The magnitude of average acceleration is 4 m/s².
🔒 Solution Hidden from View
Submit your answer to unlock the detailed step-by-step solution.
About This Question
- Subject
- physics
- Chapter
- kinematics
- Topic
- average acceleration
- Difficulty
- Easy
- Year
- 2025
Solution
Correct Answer:
4 m/s²
- Sign Convention: Let East be the positive direction (+ velocity).
- Velocity Change:
- Initial velocity u=+8 m/s.
- Final velocity v=−4 m/s (West).
- Calculate Change ((\Delta v)): Δv=v−u=(−4)−(+8)=−12 m/s.
- Acceleration Formula: aavg=ΔtΔv=3 s−12 m/s=−4 m/s2.
- Magnitude: ∣aavg∣=4 m/s2.
- Result: The magnitude of average acceleration is 4 m/s².
This easy difficulty physics question is from the chapter kinematics, covering the topic of average acceleration. It appeared in the 2025 exam.
Looking for more practice? Explore all physics questions or browse kinematics questions on RankGuru.