Aufbau And Hund's Rule
According to Hund's rule of maximum multiplicity, which electronic configuration represents the correct ground state filling of the 2p subshell with exactly three electrons?
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About This Question
- Subject
- chemistry
- Chapter
- atomic structure
- Topic
- aufbau and hund's rule
- Difficulty
- Easy
- Year
- 2025
Solution
Correct Answer:
↑inpx,↑inpy,↑inpz
Hund's rule of maximum multiplicity states that electrons occupy degenerate orbitals singly before any pairing occurs, and the singly occupied orbitals all have the same spin direction to maximize the spin multiplicity (total spin). This arrangement minimizes electron–electron repulsion by keeping electrons in separate orbitals. For three electrons in 2p: each electron enters a separate p orbital (p_x, p_y, p_z), all with the same spin (all spin-up or all spin-down). This gives ↑ in p_x, ↑ in p_y, ↑ in p_z. Option (A) is incorrect because pairing in p_x before occupying p_y and p_z violates Hund's rule. Option (B) has a paired electron in p_x while p_z is empty, again violating Hund's rule. Option (D) has mixed spins (↑ and ↓) in singly occupied orbitals, which violates the spin alignment requirement of Hund's rule. The ground state configuration described corresponds to nitrogen's 2p^3 subshell (Z=7), a classic NCERT example of Hund's rule. Plausibility check: a half-filled subshell (p^3 here) is known to be especially stable due to maximum exchange energy, consistent with all three orbitals being singly occupied with parallel spins.
This easy difficulty chemistry question is from the chapter atomic structure, covering the topic of aufbau and hund's rule. It appeared in the 2025 exam.
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