Atomic Spectra
Easyphysics
The wavelength of the first line of Balmer series in hydrogen spectrum is 656 nm. This transition is from n = 3 to:
Select the correct option:
Solution
Incorrect! Answer:
n = 2
- Definitions: The Balmer series consists of all transitions where the final orbit nf=2.
- Identify the Line: The 'first line' (longest wavelength, lowest frequency) corresponds to the transition from the next higher orbit, which is ni=3.
- Transition Details:
- n=3→n=2.
- Context: This specific line is known as the Hα line and appears in the red visible spectrum.
- Verification: Other series end at n=1 (Lyman) or n=3 (Paschen).
🔒 Solution Hidden from View
Submit your answer to unlock the detailed step-by-step solution.
About This Question
- Subject
- physics
- Chapter
- atoms and nuclei
- Topic
- atomic spectra
- Difficulty
- Easy
- Year
- 2025
Solution
Correct Answer:
n = 2
- Definitions: The Balmer series consists of all transitions where the final orbit nf=2.
- Identify the Line: The 'first line' (longest wavelength, lowest frequency) corresponds to the transition from the next higher orbit, which is ni=3.
- Transition Details:
- n=3→n=2.
- Context: This specific line is known as the Hα line and appears in the red visible spectrum.
- Verification: Other series end at n=1 (Lyman) or n=3 (Paschen).
This easy difficulty physics question is from the chapter atoms and nuclei, covering the topic of atomic spectra. It appeared in the 2025 exam.
Looking for more practice? Explore all physics questions or browse atoms and nuclei questions on RankGuru.