Aromaticity Of Charged Species
The cyclopentadienyl anion shows unusual stability for a five-membered carbanion; which property best explains this remarkable stabilisation?
Select the correct option:
Solution
It is aromatic with six delocalised pi electrons satisfying Huckel's rule
Charged cyclic conjugated species can be aromatic if, after accounting for the charge, the ring is planar, fully conjugated, and holds 4n + 2 delocalised pi electrons. The cyclopentadienyl anion has five sp^2 carbons; two double bonds supply four pi electrons and the carbanion lone pair adds two more, giving a total of six delocalised pi electrons in a planar ring. Six electrons satisfy Huckel's rule with n = 1, so the anion is aromatic and unusually stable, which is why cyclopentadiene is itself fairly acidic. The option calling it antiaromatic with four pi electrons miscounts and ignores the lone pair contribution. The option claiming it is non-planar and non-conjugated contradicts the sp^2 framework that enables full delocalisation. The option of a localised charge on one carbon is wrong because the charge is spread equally over all five carbons by resonance. This is a classic NCERT and JEE example of aromatic ions, paired in many problems with the tropylium cation, which is aromatic with six pi electrons across a seven-membered ring. The contrast with the cyclopentadienyl cation, which has only four pi electrons and is antiaromatic and unstable, sharpens the lesson that adding or removing electrons can switch a ring between aromatic and antiaromatic. Plausibility check: counting two pi bonds plus the lone pair gives six electrons, the smallest non-trivial aromatic number, which accounts for the special stability.
🔒 Solution Hidden from View
Submit your answer to unlock the detailed step-by-step solution.
About This Question
- Subject
- chemistry
- Chapter
- some basic principles of organic chemistry
- Topic
- aromaticity of charged species
- Difficulty
- Hard
- Year
- 2025
Solution
Correct Answer:
It is aromatic with six delocalised pi electrons satisfying Huckel's rule
Charged cyclic conjugated species can be aromatic if, after accounting for the charge, the ring is planar, fully conjugated, and holds 4n + 2 delocalised pi electrons. The cyclopentadienyl anion has five sp^2 carbons; two double bonds supply four pi electrons and the carbanion lone pair adds two more, giving a total of six delocalised pi electrons in a planar ring. Six electrons satisfy Huckel's rule with n = 1, so the anion is aromatic and unusually stable, which is why cyclopentadiene is itself fairly acidic. The option calling it antiaromatic with four pi electrons miscounts and ignores the lone pair contribution. The option claiming it is non-planar and non-conjugated contradicts the sp^2 framework that enables full delocalisation. The option of a localised charge on one carbon is wrong because the charge is spread equally over all five carbons by resonance. This is a classic NCERT and JEE example of aromatic ions, paired in many problems with the tropylium cation, which is aromatic with six pi electrons across a seven-membered ring. The contrast with the cyclopentadienyl cation, which has only four pi electrons and is antiaromatic and unstable, sharpens the lesson that adding or removing electrons can switch a ring between aromatic and antiaromatic. Plausibility check: counting two pi bonds plus the lone pair gives six electrons, the smallest non-trivial aromatic number, which accounts for the special stability.
This hard difficulty chemistry question is from the chapter some basic principles of organic chemistry, covering the topic of aromaticity of charged species. It appeared in the 2025 exam.
Looking for more practice? Explore all chemistry questions or browse some basic principles of organic chemistry questions on RankGuru.