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Aromatic Hydrocarbons

Mediumchemistry

Which of the following correctly describes the mechanism by which benzene undergoes reaction with bromine in the presence of FeBr₃?

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About This Question

Subject
chemistry
Chapter
hydrocarbons
Topic
aromatic hydrocarbons
Difficulty
Medium
Year
2025
Tags
Aromatic HydrocarbonsBenzeneElectrophilic Aromatic SubstitutionHalogenation

Solution

Correct Answer:

Electrophilic aromatic substitution

Benzene has a delocalized π electron cloud above and below the ring, making it nucleophilic toward electrophiles. FeBr₃ (Lewis acid) activates Br₂ by accepting a lone pair from one bromine atom: Br₂ + FeBr₃ → Br⁺···FeBr₄⁻. This generates a potent electrophile (Br⁺ equivalent). The π electrons of benzene attack this electrophile to form a carbocation intermediate called a sigma complex (arenium ion or Wheland intermediate), in which aromaticity is temporarily lost. Loss of a proton from the sigma complex restores aromaticity and regenerates the catalyst FeBr₃, yielding bromobenzene. Aromaticity is restored by elimination (not addition), making this electrophilic aromatic substitution (EAS), not electrophilic addition (which would destroy aromaticity permanently).

This medium difficulty chemistry question is from the chapter hydrocarbons, covering the topic of aromatic hydrocarbons. It appeared in the 2025 exam.

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