Anti-markovnikov Addition
Easychemistry
In presence of peroxides, HBr addition to propene gives:
Select the correct option:
Solution
Incorrect! Answer:
1-Bromopropane (major)
- Kharasch Effect: In the presence of organic peroxides (R−O−O−R), HBr adds to alkenes via a free radical mechanism instead of the standard carbocation pathway.
- Radical Generation: Peroxides initiate the cleavage of HBr to form a Bromine radical (Br⋅).
- Addition Step: The Br⋅ radical adds to the alkene first. It prefers to add to the terminal carbon to leave behind the more stable secondary radical (CH3−C˙H−CH2Br).
- Hydrogen Transfer: This secondary radical then abstracts a hydrogen atom from another HBr molecule.
- Regiochemistry: The result is Anti-Markovnikov addition, where the Bromine ends up on the terminal carbon, producing 1-Bromopropane.
- Note: This effect is highly specific to HBr (not HCl or HI).
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About This Question
- Subject
- chemistry
- Chapter
- hydrocarbons
- Topic
- anti-markovnikov addition
- Difficulty
- Easy
- Year
- 2025
Solution
Correct Answer:
1-Bromopropane (major)
- Kharasch Effect: In the presence of organic peroxides (R−O−O−R), HBr adds to alkenes via a free radical mechanism instead of the standard carbocation pathway.
- Radical Generation: Peroxides initiate the cleavage of HBr to form a Bromine radical (Br⋅).
- Addition Step: The Br⋅ radical adds to the alkene first. It prefers to add to the terminal carbon to leave behind the more stable secondary radical (CH3−C˙H−CH2Br).
- Hydrogen Transfer: This secondary radical then abstracts a hydrogen atom from another HBr molecule.
- Regiochemistry: The result is Anti-Markovnikov addition, where the Bromine ends up on the terminal carbon, producing 1-Bromopropane.
- Note: This effect is highly specific to HBr (not HCl or HI).
This easy difficulty chemistry question is from the chapter hydrocarbons, covering the topic of anti-markovnikov addition. It appeared in the 2025 exam.
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