Angular Momentum

Question

Angular momentum of particle of mass m moving with speed v in circle radius r about center is:

RankGuru · Accepted Answer

Angular momentum ($\vec{L}$) of a particle about a point is:
$\vec{L} = \vec{r} 	imes \vec{p} = \vec{r} 	imes (m \vec{v})$
For circular motion, the position vector $\vec{r}$ (from the center) is always perpendicular to the velocity vector $\vec{v}$. 
The magnitude is:
$L = r m v \sin 90^\circ = m v r$
In terms of angular velocity: $L = m(r \omega)r = m r^2 \omega = I \omega$.

Rank Guru

Angular Momentum

Select the correct option:

Solution

🔒 Solution Hidden from View

More angular momentum Practice Questions

Direction of angular momentum of a particle in uniform circular motion?

A skater decreases moment of inertia from 4 to 1 kg·m². Initial ω = 3 rad/s. Final ω?

A figure skater with arms extended has a moment of inertia of 4 kg·m² and rotates at 2 rad/s. When s...

A disc of mass 2 kg and radius 0.5 m rotates at 10 rad/s. What is its angular momentum?

Figure skater pulls arms inward reducing I to half. ω becomes:

About This Question