Angular Momentum
Easyphysics
Angular momentum of particle of mass m moving with speed v in circle radius r about center is:
Select the correct option:
🔒 Solution Hidden from View
Submit your answer to unlock the detailed step-by-step solution.
More rotational motion Practice Questions
About This Question
- Subject
- physics
- Chapter
- rotational motion
- Topic
- angular momentum
- Difficulty
- Easy
- Year
- 2025
Solution
Correct Answer:
m v r
Angular momentum (L) of a particle about a point is: L=r×p=r×(mv) For circular motion, the position vector r (from the center) is always perpendicular to the velocity vector v. The magnitude is: L=rmvsin90∘=mvr In terms of angular velocity: L=m(rω)r=mr2ω=Iω.
This easy difficulty physics question is from the chapter rotational motion, covering the topic of angular momentum. It appeared in the 2025 exam.
Looking for more practice? Explore all physics questions or browse rotational motion questions on RankGuru.