Angular Momentum
Angular momentum of particle of mass m moving with speed v in circle radius r about center is:
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Solution
m v r
Angular momentum (L) of a particle about a point is: L=r×p=r×(mv) For circular motion, the position vector r (from the center) is always perpendicular to the velocity vector v. The magnitude is: L=rmvsin90∘=mvr In terms of angular velocity: L=m(rω)r=mr2ω=Iω.
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About This Question
- Subject
- physics
- Chapter
- rotational motion
- Topic
- angular momentum
- Difficulty
- Easy
- Year
- 2025
Solution
Correct Answer:
m v r
Angular momentum (L) of a particle about a point is: L=r×p=r×(mv) For circular motion, the position vector r (from the center) is always perpendicular to the velocity vector v. The magnitude is: L=rmvsin90∘=mvr In terms of angular velocity: L=m(rω)r=mr2ω=Iω.
This easy difficulty physics question is from the chapter rotational motion, covering the topic of angular momentum. It appeared in the 2025 exam.
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