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Alkenes

Easychemistry

Markovnikov's rule predicts that the addition of HBr to propene (CH₃–CH=CH₂) will predominantly yield:

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About This Question

Subject
chemistry
Chapter
hydrocarbons
Topic
alkenes
Difficulty
Easy
Year
2025
Tags
AlkenesMarkovnikov's RuleElectrophilic AdditionHBr Addition

Solution

Correct Answer:

2-Bromopropane

Markovnikov's rule states that in electrophilic addition of a protic acid HX to an unsymmetrical alkene, the proton (H⁺) adds to the carbon bearing more hydrogens (forming the more stable carbocation), while X⁻ adds to the carbon bearing fewer hydrogens. In propene, C1 (=CH₂) bears 2 H atoms and C2 (CH=) bears 1 H atom. Protonation of C1 generates a secondary carbocation at C2 (CH₃–CH⁺–CH₃), which is more stable than the primary carbocation at C1. Br⁻ then attacks C2, giving 2-bromopropane (CH₃CHBrCH₃) as the major product. 1-Bromopropane would form from the less stable primary carbocation and is the minor product.

This easy difficulty chemistry question is from the chapter hydrocarbons, covering the topic of alkenes. It appeared in the 2025 exam.

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