Aldehydes And Ketones - Cross Aldol Condensation
Benzaldehyde and propanone are warmed together with dilute base in a crossed aldol condensation, so which conjugated product predominates after dehydration?
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Solution
Benzalacetone(4−phenylbut−3−en−2−one)
A crossed aldol condensation works cleanly when one partner has no alpha-hydrogen and therefore cannot form an enolate, leaving only the other partner to act as the nucleophile. Benzaldehyde has no alpha-hydrogen, so it serves purely as the electrophilic carbonyl, while propanone supplies the enolate from its alpha-carbon. The enolate of propanone adds to the benzaldehyde carbonyl, and subsequent dehydration gives the conjugated ketone benzalacetone, 4-phenylbut-3-en-2-one, as the major product when reagents are in modest ratio. Cinnamaldehyde is wrong because it would require an acetaldehyde-derived enolate adding to benzaldehyde, not propanone. Dibenzalacetone forms only with excess benzaldehyde reacting at both alpha-positions of propanone, so it is not the predominant single-condensation product described. The non-dehydrated beta-hydroxy ketone is only an intermediate and is removed on heating. This selective crossed condensation is emphasised in advanced organic discussions and is a classic JEE Advanced question. The practical lesson is that a crossed aldol is only synthetically useful when one carbonyl cannot enolise, otherwise four different products form and the mixture is useless; pairing an aromatic aldehyde with a ketone is the standard way to exploit this, a transformation often called the Claisen-Schmidt condensation. Using excess benzaldehyde deliberately converts both alpha-positions to give the symmetric dibenzalacetone instead. As a check, the alpha-hydrogen-free aldehyde behaves as the electrophile while the ketone supplies the nucleophile, giving benzalacetone.
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About This Question
- Subject
- chemistry
- Chapter
- organic compounds containing oxygen
- Topic
- aldehydes and ketones - cross aldol condensation
- Difficulty
- Hard
- Year
- 2025
Solution
Correct Answer:
Benzalacetone(4−phenylbut−3−en−2−one)
A crossed aldol condensation works cleanly when one partner has no alpha-hydrogen and therefore cannot form an enolate, leaving only the other partner to act as the nucleophile. Benzaldehyde has no alpha-hydrogen, so it serves purely as the electrophilic carbonyl, while propanone supplies the enolate from its alpha-carbon. The enolate of propanone adds to the benzaldehyde carbonyl, and subsequent dehydration gives the conjugated ketone benzalacetone, 4-phenylbut-3-en-2-one, as the major product when reagents are in modest ratio. Cinnamaldehyde is wrong because it would require an acetaldehyde-derived enolate adding to benzaldehyde, not propanone. Dibenzalacetone forms only with excess benzaldehyde reacting at both alpha-positions of propanone, so it is not the predominant single-condensation product described. The non-dehydrated beta-hydroxy ketone is only an intermediate and is removed on heating. This selective crossed condensation is emphasised in advanced organic discussions and is a classic JEE Advanced question. The practical lesson is that a crossed aldol is only synthetically useful when one carbonyl cannot enolise, otherwise four different products form and the mixture is useless; pairing an aromatic aldehyde with a ketone is the standard way to exploit this, a transformation often called the Claisen-Schmidt condensation. Using excess benzaldehyde deliberately converts both alpha-positions to give the symmetric dibenzalacetone instead. As a check, the alpha-hydrogen-free aldehyde behaves as the electrophile while the ketone supplies the nucleophile, giving benzalacetone.
This hard difficulty chemistry question is from the chapter organic compounds containing oxygen, covering the topic of aldehydes and ketones - cross aldol condensation. It appeared in the 2025 exam.
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